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shutvik [7]
3 years ago
12

Fifty six students sing up to volunteer for the race . There were 4 equal groups of students , and each group had a different ta

sk. How many students were in each group?
Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0
There were 14 students per group.
You might be interested in
Anyone know the answers to this ?!
torisob [31]

Answer:

Hey there!

3 x 5/4 = 3 x 5 ÷ 4 = 5 x 3 ÷ 4

5 x 4/3 = 5 x 4 ÷ 3 = 4 x 5 ÷ 3

4 x 3/5 = 4 x 3 ÷ 5 = 4 x 3 ÷ 5

Hope this helps :)

5 0
2 years ago
Which shows the expression below simplified? 0.00048 - (3.4 × 10-5) A. 4.46 × 10-4 B. 3.39952 × 10-5 C. 4.46 × 10-5 D. 1.4 × 10-
MakcuM [25]

Option C

The simplified form of given expression is 4.46 \times 10^{-4}

<em><u>Solution:</u></em>

Given that we have to simplify the expression shown below

0.00048 - (3.4 \times 10^{-5})

Let us first convert 0.00048 to scientific notation

<em><u>Steps to follow:</u></em>

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

If you did not need to move the decimal b = 0.

Write your scientific notation number as a x 10^b and read it as "a times 10 to the power of b."

Remove trailing 0's only if they were originally to the left of the decimal point.

0.00048 = 4.8 \times 10^{-4}

So the given expression becomes,

\rightarrow 4.8 \times 10^{-4} - 3.4 \times 10^{-5}

Let us make the exponent of second term as -4

\rightarrow 4.8 \times 10^{-4} - 0.34 \times 10^{-4}

Take 10^{-4} as common term,

\rightarrow 10^{-4} (4.8 - 0.34)

\rightarrow 4.46 \times 10^{-4}

Thus option C is correct

7 0
3 years ago
Write each repeating decimal using bar notation.
Ahat [919]

Answer:

  ___

2.034

over .034

     _

0.92

over 2

  _

0.7

over 7

Step-by-step explanation:

3 0
2 years ago
1. Find the length a.
stellarik [79]
Use the Pythagorean Theorem to find the missing lengths<span> of the </span>sides<span> of a right triangle.  triangle that has an opposite </span>side<span> of </span>length 3<span> and a hypotenuse of </span>length<span> 4.  </span>Determining<span> all of the </span>side lengths<span>and angle measures of a right triangle is  Let's look at how to do this when you're given </span>one side length<span>and </span>one<span> acute</span>
7 0
3 years ago
In class, 5/9 of the students have blue Eyes. if 10 students have blue eyes, how many students are in the class in total?
KiRa [710]
Let us cross multiply.

5/9=10/x

9 x 10= 5x

90=5x

90 <u />÷ 5= 5x <span>÷ 5

18=x

So, the answer is 18. I hope this helped you, since I just learned cross multiplication last week.</span>
8 0
2 years ago
Read 2 more answers
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