Answer:
Step-by-step explanation:
y = -5x - 17
in y = mx + b form, the y int is in the m position
y = mx + b
y = -5x - 17......so the y int (b) = -17 or (0,-17) <=== y intercept
u can also find the y intercept by subbing in 0 for x and solving for y
u can find the x intercept by subbing in 0 for y and solving for x
y = -5x - 17
0 = -5x - 17
5x = -17
x = -17/5......so the x intercept is -17/5 or (0,-17/5) <==== x intercept
The answer is 1351 I know this because I did all the math
Answer:
67
Step-by-step explanation:
To round 67.498 to the nearest whole number consider the tenths’ value of 67.498, which is 4 and less than 5. Therefore, we have to round down: the whole number ones place value of 67.498, 67, remains 67, and the decimal point and all digits (.498) are removed.
67.498 rounded to the nearest whole number = 67
Answer:
Step-by-step explanation:
Here, you can use a simple formula.
To find the point of intersection you just put x=0 or y=0.
Because, if a graph intersects x-axis, then at this point y=0
Similarly, if a graph intersects y-axis, then at this point x=0
So, for our given line.
y=-1/4 x +2
when , x=0 , y=-1/4 (0)+2=2
So, the graph intersects y-axis at y=2
when , y=0 ,
then 0=-1/4 x+2
or, 1/4 x=2
or, x=8 [multiplying by 4]
So, the graph intersects x-axis at x=8
I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,




So, 

So, 
Hope this helps you!