1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlladinOne [14]
3 years ago
13

A sign in front of a roller coaster says "You must be 40 inches tall to ride."

Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

54/40 = 1.35 or 135%

Step-by-step explanation:

You might be interested in
Solve for "r":<br> 4/3πr^3 = V
boyakko [2]
\frac{4}{3} \pi r^3=V&#10;\\&#10;\\4\pi r^3=3V&#10;\\&#10;\\ r^3= \frac{3V}{4\pi}&#10;\\&#10;\\r= \sqrt[3]{\frac{3V}{4\pi}}
8 0
4 years ago
20a + 158 + 6c = 20 ( 6 ) + 15 (4) + 6 (8)
elixir [45]

Answer:

28 plus tht 58

gghhjjjiijcddc viii kiub

5 0
3 years ago
Read 2 more answers
The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St
saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(domestic airfare is $550 or more)

P(x > 550)

P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)

= 1 - P(z \leq 1.5)

Calculation the value from standard normal z table, we have,  

P(x > 550) = 1 - 0.933 = 0.067= 6.7\%

b) P(domestic airfare is $250 or less)

P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)

Calculating the value from the standard normal table we have,

P( x \leq 250) = 0.111 = 11.1\%

c))P(domestic airfare is between $300 and $500)

P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%

P(300 \leq x \leq 500) = 61.2\%

d) P(X=x) = 0.03

We have to find the value of x such that the probability is 0.03.

P(X > x)

P( X > x) = P( z > \displaystyle\frac{x - 385}{110})=0.03

= 1 -P( z \leq \displaystyle\frac{x - 385}{110})=0.03

=P( z \leq \displaystyle\frac{x - 385}{110})=0.997

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 385}{110} = 2.748\\x = 687.28

Hence, the domestic fares must be $687.28 or greater for them to lie in the highest 3%.

7 0
3 years ago
Can someone help me with this please?!?!?!?
dusya [7]
Answer

17 m^3

Explanation

Volume of a given prism = bh

Where b = base area and h = height of prism

Base area = 1 • 2/2 (b • h /2)

= 1

Height = 17

17 • 1 = 17 m^3
5 0
3 years ago
RECTANGLE ABCD has vertices A(-5,2) B(-5,4) C(4,4) D(4,2) calculate the area.
Assoli18 [71]

Answer:

18

Step-by-step explanation:

9*2 square

6 0
3 years ago
Other questions:
  • What is the graph of the function f(x) = -x^2 + 4x +6/x+4
    15·1 answer
  • Evaluate the function.<br> f(x)=-2x^2-7x+6<br><br> Find f(−3)
    11·1 answer
  • If a real estate agent sold a piece of land for 580000. how much commission did he/she get at 2.5%​
    9·1 answer
  • Shelia mows 1/6 acre in 1/4 hour. How many acres does she mow in per hour?
    7·1 answer
  • Please answer with explanation
    14·1 answer
  • Find the MEAN, MODE, MEDIAN, and RANGE for the following Data: 6, 8,4, 1,4,7
    15·1 answer
  • Tell whether each statement about the expression 5y + 9 is True or False
    13·1 answer
  • La tercera parte de la suma entre un numero y 5 es 4<br>Me ayudan?​
    12·1 answer
  • Solve the system of linear equations by elimination.<br><br> 2x+5y=16<br> 3x−5y=−1<br><br> Get (x,y)
    9·2 answers
  • How much less is the area of a rectangular field 70 by 30 meters than that of a square field with the same perimeter?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!