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2 years ago

What is Perpendicular Slice? is up or down or Left to Right I Forgot

Mathematics

2 answers:

Nikolay [14]2 years ago

4 0

Answer:

up and down

Step-by-step explanation:

BigorU [14]2 years ago

4 0

Answer:

Im pretty sure its up to down

Step-by-step explanation:

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Yes or no please, question in picture

Nataly [62]

Answer:

yes

Step-by-step explanation:

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2 years ago

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In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to

brilliants [131]

If he got 5 points in the first round and he needed at least thirty he would score 9 points in the next three rounds

8 0

2 years ago

Find f(-3) if f(x) = x 2.

vlabodo [156]

Answer:

f(-3) = 9

Step-by-step explanation:

Lets define f(a) first where a is any integer,

f(a) is found out by putting the integer in the function in place of the variable

So for the given question

$f(x) = x^{2}$

In order to find f(-3) we will put -3 in place of x

So putting -3,

$f(-3) = (-3)^{2}$

$f(-3) = 9$

So, the value of function at -3 is 9 ..

5 0

2 years ago

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I need help plz someone

stich3 [128]

Answer:

5C 6D

Step-by-step explanation:

5, a^2 = b^2 + c^2

A is wrong because two distinct lines intersect at 1 point only or 0 (they will never intersect when they are parallel)

B & C are wrong because lines contain infinite point

E is wrong because 2 parallel lines will never intersect, as the result, their common points = 0

6 0

3 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago