Ask question

Ask question

All categories

3 years ago

8

Hi help meeeeeeee please i will mark you brainiest if you can answer this

1 answer:

Roman55 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Honestly don't even care about the points lol. You need to divide 12^7 by 12^3, which comes out to 20,736 crates needed for the shipment of toys. If that first 12 isnt to the power of 3 simply replace it with the power that it actually is and divide 12^7 by it.

You might be interested in

Point A is plotted at (-5, 3)

Diano4ka-milaya [45]

Answer:

quadrant 1

Step-by-step explanation:

quadrant 1 is (-,+)

5 0

3 years ago

r-ruslan [8.4K]

The answer is B. y = -1/5x +1/2.

EXPLANATION

First solve for the slope:
$m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{0 - \frac{3}{5} }{ \frac{1}{2} - \frac{1}{5} } \\ m = - \frac{1}{5}$
After finding the slope, look for the linear equation with the same value of m (parallel equation).

4 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

help me brainlist if you right Mona is inviting 10 friends to a party. Each friend wants 5 cookies and each box has 10 cookies.

seropon [69]

Answer:

its 5 boxes

Step-by-step explanation:

5 0

2 years ago

I dont understand and i would like some help understanding this -4(y-6) ≤ (-9+y)(-2)

Oliga [24]

Answer:

Y greater than or equal to 6

Step-by-step explanation:

I can't do the sign so I just said it

Combine like terms

6 0

3 years ago

Read 2 more answers