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densk [106]
3 years ago
12

Find the perimeter of a triangle with sides 12 inches, 9 inches, and 15 inches.

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0
If its perimeter, it should be quite easy to find. Just add 12+9+15. Which equals 36. So the perimeter is 36 inches. -Hope it helps!
kogti [31]3 years ago
7 0
Hi there! P=L+W+H. It really doesn't matter what the length, width, and height is when your dealing with perimeter. In this case, the length is 12 inches, the width is 9 inches and the height is 15 inches. 12 inches+9inches+15inches=36 inches. Therefore, the answer is 36 inches.
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2 years ago
Determine whether each expression can be used to find the length of side AB. Match Yes or No for each
tankabanditka [31]

Answer:

(a)\ AB = \frac{7}{\sin (B)}  \to Yes

(b)\ AB = \frac{24}{\cos (B)} \to Yes

(c)\ AB = \frac{24}{\cos (A)} \to No

(d)\ AB = \frac{7}{\cos (A)}  \to Yes

Step-by-step explanation:

Given

BC =24

AC = 7

Required

Select Yes or No for the given options

(a)\ AB = \frac{7}{\sin (B)}  \to Yes

Considering the sine of angle B, we have:

\sin(B) = \frac{Opposite}{Hypotenuse}

\sin(B) = \frac{7}{AB}

Make AB, the subject

AB = \frac{7}{\sin(B)}

(b)\ AB = \frac{24}{\cos (B)} \to Yes

Considering the cosine of angle B, we have:

\cos(B) = \frac{Adjacent}{Hypotenuse}

\cos(B) = \frac{24}{AB}

Make AB the subject

AB = \frac{24}{\cos(B)}

(c)\ AB = \frac{24}{\cos (A)} \to No

Considering the cosine of angle B, we have:

\cos(A) = \frac{Adjacent}{Hypotenuse}

\cos(A) = \frac{7}{AB}

Make AB the subject

AB = \frac{7}{\cos(A)}

(d)\ AB = \frac{7}{\cos (A)}  \to Yes

<em>This has been shown in (c) above</em>

3 0
3 years ago
By how much is 3 4/5 greater than the product of 3/5 x 1 3/4
dalvyx [7]

Answer: 6.65

Step-by-step explanation:

3 4/5 = 3.8

1 3/4 = 1.75

3.8*1.75= 6.65

Hope it helps <3

7 0
3 years ago
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