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3 years ago

Solve and explain please

Mathematics

1 answer:

butalik [34]3 years ago

6 0

Answer:

b = √79

Step-by-step explanation:

using pythagorath's theorem

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Complementary angles always sum to _____. a. 0° b. 45° c. 90° d. 180°

skelet666 [1.2K]

D, 180 always 180 degrees

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4 years ago

42+__________=68 vhrvwfruybtglh

Hitman42 [59]

Answer:

42 + 26 = 68

Step-by-step explanation:

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3 years ago

Find the angle between vector u=2i+sqrt(11)j and v=-3i-2j to the nearest degree

const2013 [10]

Answer: Last option 155°

Step-by-step explanation:

We have the components of the vectors u and v.

Then, to find the angle between them, perform the following steps:

1) Calculate the scalar product u * v

If $u = 2i + \sqrt{11}j$ and $v = -3i-2j$

Then, the product scalar u * v is:

$u * v = (2)(-3) + (\sqrt{11})(-2)$

$u * v = -6-2\sqrt{11}$

$u * v = -12.633$

2) Calculation of the magnitude of both vectors.

$| u | = \sqrt{(2) ^ 2 + (\sqrt{11})^2}\\\\| u | = \sqrt{4+11}\\\\| u | = \sqrt{15}$

$| v | = \sqrt{(- 3) ^ 2 + (- 2) ^ 2}\\\\| v | = \sqrt{9 +4}\\\\| v | = \sqrt{13}$

3) Now that you know the product point between the two vectors and the magnitude of each, then use the following formula to find an angle

$u * v = | u || v |cos(\alpha)$

$-12.633 = \sqrt{15}\sqrt{13}*cos(\alpha)\\\\cos(\alpha) = \frac{-12.633}{\sqrt{15}\sqrt{13}}\\\\arcos(\frac{-12.633}{\sqrt{15}\sqrt{13}}) = \alpha\\\\\alpha =155\°$

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4 years ago

Find the greatest common factor of<br><br> 10x+25y+5

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Answer:

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3 years ago

The mass of an electron is approximately 9.1 x 10^-31 kilograms.

Brut [27]

Answer:

1900

Step-by-step explanation:

hello bro how r u i think answer is 1835 but there is no option

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3 years ago

Read 2 more answers