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Alik [6]
3 years ago
12

Im not sure what to do for this problem

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0
325/360=120 πr2
325 πr2/325 π=120.360/325 π
R2=42.3
R=6.5cm is your answer
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Step-by-step explanation:

Since c^2<a^2+b^2, it is an acute triangle.

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How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the populati
marshall27 [118]

Using the z-distribution, it is found that a sample of 171 should be selected.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
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For this problem, the parameters are:

z = 1.96, \sigma = 40, M = 6

Hence we solve for n to find the needed sample size.

M = z\frac{\sigma}{\sqrt{n}}

6 = 1.96\frac{40}{\sqrt{n}}

6\sqrt{n} = 40 \times 1.96

\sqrt{n} = \frac{40 \times 1.96}{6}

(\sqrt{n})^2 = \left(\frac{40 \times 1.96}{6}\right)^2

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Rounding up, a sample of 171 should be selected.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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