Answer:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Step-by-step explanation:
For this case we can estimate the population proportion of people that they did work at home at least once per week with this formula:

We need to find the critical value using the normal standard distribution the z distribution. Since our condifence interval is at 99%, our significance level would be given by
and
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
If we replace the values obtained we got:
The 99% confidence interval would be given by (0.054;0.154)
. So we are confident at 99% that the true proportion of people that they did work at home at least once per week is between 0.054 and 0.154
Answer: He ended up with about 1 pound less grapes
Step-by-step explanation:
2 bags of grapes weighing 5 and two-thirds pounds each will give a total weight of:
= 2 × 5 2/3
= 2 × 17/3
= 34/3
= 11 1/3 pounds
3 bags weighing 4 and one-fifth pounds each, will give a weight of:
= 3 × 4 1/5
= 3 × 21/5
= 63/5
= 12 3/5
He ended up buying lesser grapes. This was about 12 3/5 - 11 1/3 = 1 4/15 less. This means that he ended up with about 1 pound less grapes
1 16oz = $1
40=16*4
1 40oz = $4
8*$4 = $32
Answer:
Step-by-step explanation:
Hello, your question is not mathematically solvable.