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Anna71 [15]
3 years ago
8

What is this angle? plz help

Mathematics
2 answers:
Anon25 [30]3 years ago
6 0

Answer:

56 degrees

Step-by-step explanation:

a straight angle is 180 degrees so you subtract 180 and  124 and get 56

wolverine [178]3 years ago
5 0

Answer: 56 degrees

Step-by-step explanation:

Line AD is supplementary, therefore subtracting 180 from 124 is 56 degrees.

Brainiest help

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The equation 6y = 30 - 8x has solutions of (b, 1) and (a, b).<br> What are the values of a and b?
victus00 [196]

The values of a and b are a = \frac{3}{2} and b = 3, respectively.

In this question we need to solve the linear equation for each point, first for (x,y) = (b, 1) and later for (x,y) = (a, b).

If we know that (x,y) = (b, 1), then the value of b is:

6 = 30-8\cdot b

8\cdot b = 24

b = 3

If we know that (x,y) = (a, b) and b = 3, then the value of a is:

6\cdot b = 30 - 8\cdot a

18 = 30-8\cdot a

12 = 8\cdot a

a = \frac{3}{2}

The values of a and b are a = \frac{3}{2} and b = 3, respectively.

To learn more on linear functions, we kindly invite to check this question: brainly.com/question/5101300

6 0
3 years ago
-6 - 8 is equivalent to?<br> 6 + (-8)<br> -6 + 8<br> 6 + 8<br> -6 + (-8)
nadezda [96]
It is equivalent to:
-6 + (-8)
7 0
4 years ago
Read 2 more answers
A geometric sequence is defined by the equation an = (3)3 − n.
Delvig [45]
PART A

The geometric sequence is defined by the equation

a_{n}=3^{3-n}

To find the first three terms, we put n=1,2,3

When n=1,

a_{1}=3^{3-1}

a_{1}=3^{2}

a_{1}=9
When n=2,

a_{2}=3^{3-2}
a_{2}=3^{1}

a_{2}=3

When n=3

a_{3}=3^{3-3}

a_{3}=3^{0}
a_{1}=1
The first three terms are,

9,3,1

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
r= \frac{a_{2}}{a_{1}}
r = \frac{3}{9}

r = \frac{1}{3}

PART C

To find
a_{11}

We substitute n=11 into the equation of the geometric sequence.

a_{11} = {3}^{3 - 11}

This implies that,

a_{11} = {3}^{ - 8}

a_{11} = \frac{1}{ {3}^{8} }

a_{11}=\frac{1}{6561}
4 0
3 years ago
The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.
Kryger [21]

Hi There!

---------------------------------------------------------

Full Question:

The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.

Which can you tell about the mean temperatures for these two months?

There is not enough information to determine the mean temperatures.

The mean temperature for August is higher than June's mean temperature.

The mean temperature for June is equal to the mean temperature for August.

The high interquartile range for August pulls the mean temperature above June's mean temperature.

---------------------------------------------------------

Interquartile Range Formula: Q3 - Q1

Interquartile Range for August: 10

Interquartile Range for June: 8

---------------------------------------------------------

Median = Mean

June: 82

August: 82

---------------------------------------------------------

Answer: The mean temperature for June is equal to the mean temperature for August.

---------------------------------------------------------

Hope This Helps :)

5 0
3 years ago
40+30+45+50+23+7+15+6+4+10=?
Sergeu [11.5K]

The answer is 230. Good luck

7 0
4 years ago
Read 2 more answers
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