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3 years ago

PLSSSS HELPPPPP ASAP

Mathematics

1 answer:

jolli1 [7]3 years ago

6 0

D.

Perimeter is when you add and not multiple:)

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Need help please assist me find the area of a regular hexagon

garri49 [273]

Answer:

The area of the regular hexagon is $166.3\ units^{2}$

Step-by-step explanation:

we know that

The area of a regular hexagon can be divided into 6 equilateral triangles

step 1

Find the area of one equilateral triangle

$A=\frac{1}{2}(b)(h)$

we have

$b=r=8\ units$

$h=4\sqrt{3}\ units$ ----> is the apothem

substitute

$A=\frac{1}{2}(8)(4\sqrt{3})$

$A=16\sqrt{3}\ units^{2}$

step 2

Find the area of 6 equilateral triangles

$A=(6)16\sqrt{3}=96\sqrt{3}=166.3\ units^{2}$

7 0

2 years ago

Which of the following tables represent linear relationships?

ladessa [460]

Answer:

Table 2 and 3

Step-by-step explanation:

A linear relationship should show a straight line, showing that it's linear.

*View the attached graphs*

Hope this helps!

3 0

2 years ago

How to find unknown side

Elan Coil [88]

Answer:

C = 10

Step-by-step explanation:

Find the last side of the triangle using the Pythagorean theorem.

$a^{2} +b^{2} =c^{2}$

You have a and b already, a = 6, b = 8

$6^{2} +8^{2} =c^{2} \\\\$

solve this to get

$64 + 36 = \sqrt{100}$

C = 10

Apply the same to the other 2 triangles. C is your longest side!

3 0

2 years ago

Find the slope of (1,-3) (-5,3)

morpeh [17]

The slope would be -1

5 0

3 years ago

Read 2 more answers

⦁ Determine if the equation represents a direct variation. .8x = 1.6y ⦁ Suppose y varies directly with x. Write a direction vari

Mkey [24]

Part A:

Given that

$0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y$

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

$5=2k \\ \\ \Rightarrow k=\frac{5}{2} =2.5 \\ \\ \Rightarrow y=2.5x$

When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

$9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x$

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is $y=-\frac{3}{2}x$

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

$1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x$

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.

8 0

3 years ago

Read 2 more answers