The first term of the arithmetic progression exists at 10 and the common difference is 2.
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How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
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507/17576 or 0.0288
you take all the probabilities separate then multiply them all together. Then Simplify
Answer:
2⋅2⋅2⋅5=40 2 ⋅ 2 ⋅ 2 ⋅ 5 = 40
Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.
Ann (A): A
Zoe (Z): A = Z - 12 → Z = 12 + A
Jim (J): A = J - 16 → J = 16 + A
A + Z + J = 154
(A) + (12 + A) + (16 + A) = 154
3A + 28 = 154
3A = 126
A = 42
Ann (A): A = 42
Zoe (Z): Z = 12 + A = 12 + 42 = 54
Jim (J): J = 16 + A = 16 + 42 = 58
Answer: Ann=42, Zoe=54, Jim=58