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butalik [34]
3 years ago
12

verify that 1,-1,-3 are the zeroes of the cubic polynomial x3+3x2-x-3 and check the relationship between zeroes and the coeffici

ent​
Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer: yea its 123445

Step-by-step explanation:

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How to solve the problem
WINSTONCH [101]
As tgose lines are parallel then,

a = 140° ( by alternate interior angles)

then,
tha angle just below "a" on the other paralle line would also be 140° by corresponding angles,

using exterior angle property of triangle

66° + b = 140°

b = 140° -66
= 74°
7 0
3 years ago
PLEASE MATH HELP 20 points PLEASE!!!!
blsea [12.9K]
Y = 18( 0.58) ^t

It would be written as :
Y = 18(0.11) ^ (t/4)
Y = 18 (0.11 ^ (1/4)) ^ t
But
0.11 ^ (1/4) = 0.5759

Plug the value

Y = 18 (0.5759) ^ t

Two decimal point :

Y = 18 (0.58) ^ t
7 0
2 years ago
The population of a town is 32600 about 27% are over 60 years old about 19% are 16 or under how many are between 16 and 60
r-ruslan [8.4K]
Answer: 17604

Explanation: In order to find a percentage, mulptiply the population by the percentage with a decimal in front. Like this:

32600 • .46

I got 46 because 27 + 19 = 46

Once you get that answer, subtract it from the original total

32600 - 14996 = 17604

You're done! Hope this helps



3 0
2 years ago
As inflation increases, it causes the money you earn today to have _____. less value in the future more purchasing power in the
Anika [276]

Answer:

This answer is A

Step-by-step explanation:

your welcome, im fast to answer

5 0
3 years ago
Read 2 more answers
Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping once our sum exceeds 307. Approximate th
SOVA2 [1]

Answer:

There is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

Step-by-step explanation:

The roll of a six-sided die sum has this parameters:

Mean: 3.5

Standard deviation: 1.7

If the die is rolled 81 times, the distribution of the sum of the 81 rolls will have the following parameters:

\mu=n*M=81*3.5=283.5\\\\\sigma=\sqrt{n}s=\sqrt{81}*1.7=9*1.7=15.3

Note: the variance of the sum of random variables is equal to the sum of the variance of the individual variables.

Then, we can calculate the probabilties that the sum of 81 rolls is lower than 307.

z=\frac{x-\mu}{\sigma}=\frac{307-283.5}{15.3}=  \frac{23.5}{15.3}= 1.536\\\\\\P(x

There is 94% of chances that the sum of 81 rolls is lower than 307, so there is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

5 0
3 years ago
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