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borishaifa [10]
3 years ago
8

Are the ratios 4:18 and 2:9 equivalent? yes no

Mathematics
2 answers:
V125BC [204]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

SIZIF [17.4K]3 years ago
8 0

Step-by-step explanation:

Two ratios are given to us and we need to tell whether they are equivalent or not . Firstly let us say we have two ratios q:p and r:s . Here p & q are co-primes and r & s are also co-primes. Then the two ratios will be equal if and only if

  • q = r
  • p = s .

Theefore , the Ratios are ,

\begin{cases}\tt 4 : 18 \\\tt 2:9 \end{cases}

Here we see that the ratio 2:9 is in simplest form that is HCF of 2 & 9 is 1 . But here 4:18 is not in simplest form . HCF of 4 & 18 is not 1 it's 2 .On dividing numerator and denominator by 2 , we have ,

\tt= \dfrac{4}{18}\\\\ = \tt \dfrac{4 \div 2}{18\div 2}\\\\ = \boxed{\orange{\tt \dfrac{2}{9}}}

Therefore since the Ratios are equal in the simplest form . Therefore the Ratios are equal.

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Story : A Dog’s Tale by Mark Twain

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• objectivity
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• Simile
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4. According to the author, what would bring such happiness to the dogs as he describes at the end of the story?

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6 0
3 years ago
Read 2 more answers
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

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