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Mariana [72]
3 years ago
13

Alex scored 98,72, and 87 on his first three math test. What must he score on the next test to have an average of at least 86 (P

.S I need quickly no need to rush yourself just quickly)
Mathematics
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

\huge\boxed{\text{At least an } 87\%}

Step-by-step explanation:

In order to find what score Alex must earn to have an average of 86 on all his tests, we need to first note what the formula to find the average of a data set is.

\displaystyle \frac{x_1+x_2+...x_n}{n}

What the formula means is that we have to add up all the values then divide by the total number of values.

Let's represent our unknown number as x.

\displaystyle \frac{98+72+87+x}{4} \geq 86 (since we want AT LEAST an 86).

Let's solve this inequality for x.

  • \frac{98+72+87+x}{4} \cdot 4 \geq 86 \cdot 4
  • 98+72+87+x \geq 344
  • 257 + x \geq 344
  • 257 + x  - 257 \geq 344 - 257
  • x \geq 87

So, Alex must score at least an 87% on his next quiz to have an average of 86%.

Hope this helped!

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On the graph, two right triangles have the line as the hypotenuse. In this task, you will use these triangles to show that the s
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Step-by-step explanation:

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OBSERVATION A person standing 100 feet from the bottom of a cliff notices a tower on top of the cliff. The angle of elevation to
vekshin1

Answer:

The tower is 102.26 feet tall.

Step-by-step explanation:

We have drawn the triangle for your reference.

According to the figure point 'A' is the persons eye.

Point 'B' is the bottom of the cliff.

Point 'C' is the top of the cliff.

And Point 'D' is the top of the tower.

Given,

A person standing 100 feet from the bottom of a cliff notices a tower on top of the cliff.

So from diagram we can say that;

Length of AB = 100 ft

The angle of elevation to the top of the cliff is 30°.

So from diagram we can say that;

∠CAB = 30°

the angle of elevation to the top of the tower is 58°.

So from diagram we can say that;

∠DAB = 58°

We have to find the height of the tower i.e. CD.

Solution,

In ΔCAB,

∠CAB = 30°

AB = 100 ft

Now according to trigonometric  ratios;

tan\theta=\frac{opposite\ side}{adjacent\ side}

Substituting the values we get;

tan\ 30\° = \frac{BC}{100}

Now

tan\ 30\° = \frac{1}{\sqrt{3}}

So

\frac{1}{\sqrt{3}} = \frac{BC}{100}\\\\BC =\frac{100}{\sqrt{3}} = 57.74 \ ft

In ΔDAB,

∠DAB = 58°

AB = 100 ft

Now according to trigonometric  ratios;

tan\theta=\frac{opposite\ side}{adjacent\ side}

Substituting the values we get;

tan\ 58\° = \frac{BD}{100}

Now

tan\ 58\° = 1.60

So

1.60 = \frac{BD}{100}\\\\BD =100\times 1.6 = 160 \ ft

Now BD = BC + CD

CD = BD - BC = 160 - 57.74 = 102.26 ft

Hence The tower is 102.26 feet tall.

6 0
4 years ago
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