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Over [174]
2 years ago
8

2x+y=5 , 3x+2y=8 solve using cross multiplication​

Mathematics
1 answer:
Xelga [282]2 years ago
5 0

Answer:

x=2

y=1

Step-by-step explanation:

2x+y=5

3x+2y= 8

<=> 6x+3y=15

6x+4y=16

<=> -y=-1

2x+y=5

<=> y=1

2x+1=5

<=> y=1

2x=4

<=> y=1

x=2

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Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

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Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

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1
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