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Softa [21]
4 years ago
8

For the inverse variation equation xy = k, what is the value of x when y = 4 and k = 7? 3 28

Mathematics
2 answers:
Oliga [24]4 years ago
7 0

Answer:

The value of x is \frac{7}{4}.

Step-by-step explanation:

It is given that the inverse variation equation is

xy=k                  ..... (1)

The value of y is 4 and the value of k is 7.

Substitute y=4 and k=7 in equation (1).

x\times 4=7

Divide both sides by 4.

\frac{x\times 4}{4}=\frac{7}{4}

x=\frac{7}{4}

Therefore the value of x is \frac{7}{4}.

Andre45 [30]4 years ago
5 0
It would be 7/4 or 1.75 if needed to be in decimal format.
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Write an equation for the nth term of the arithmetic sequence.<br> 17, 12, 7, 2, ...<br> an=
Lorico [155]

Answer:

An equation for the nth term of the arithmetic sequence 17, 12, 7, 2 is 17-5n.

Step-by-step explanation:

Given,

first term(a)=17

common difference (d)=t2-t1

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nth term of the arithmetic sequence = a+n×d

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5 0
3 years ago
The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 15 minute
madam [21]

Answer:

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

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So a = 3, b = 15

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Either she has to wait 11 or less minutes for the bus, or she has to wait more than 11 minutes. The sum of these probabilities is 1. So

P(X \leq 11) + P(X > 11) = 1

We want P(X > 11). So

P(X > 11) = 1 - P(X \leq 11) = 1 - \frac{11 - 3}{15 - 3} = 0.3333

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

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3 years ago
Pls help me guys!<br> Thanks :D
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