Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.

Answer 1

Answer:

$CD\approx0.2$

Step-by-step explanation:

By the tangent ratio, $tanC=\frac{DB}{CD}$. Substituting the given values into this equation gives us:

$tan83$° $= \frac{1.3}{CD}$

$CD*tan83$° $=1.3$ (Multiply both sides of the equation by $CD$)

$CD=\frac{1.3}{tan83\textdegree}$ (Divide both sides of the equation by $tan83\textdegree$)

$CD=0.15962\approx0.2$

Hope this helps!