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Iteru [2.4K]
2 years ago
13

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.

Mathematics
1 answer:
Lina20 [59]2 years ago
3 0

Answer:

CD\approx0.2

Step-by-step explanation:

By the tangent ratio, tanC=\frac{DB}{CD}. Substituting the given values into this equation gives us:

tan83° = \frac{1.3}{CD}

CD*tan83° =1.3 (Multiply both sides of the equation by CD)

CD=\frac{1.3}{tan83\textdegree} (Divide both sides of the equation by tan83\textdegree)

CD=0.15962\approx0.2

Hope this helps!

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