
The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is

.
So the desired probability is
2/3 and 8/12 are proportional but 3/14 and 8/28 aren’t
The first triangle does. That's the right answer.
- Sample space = {TT, HH, TH, HT} where T is tail and H is head.
- Number of outcomes = 4
- The probability of getting two heads on tossing two coins

<u>Answer</u><u>:</u>
<u>D)</u><u> </u><u>2</u><u>5</u><u>%</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
f(x)=5x-6
Step-by-step explanation:
When I entered this in Desmos it crossed through the line crossed through the x and y axis which makes this equation a linear function.