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tankabanditka [31]
3 years ago
15

Explain how you would round 39an 88

Mathematics
2 answers:
dedylja [7]3 years ago
7 0
Depends what your talking about but the easy way is 40 and 90 
lozanna [386]3 years ago
6 0
39 rounded to the tens place would be 40.
88 rounded to the tens place would be 90.
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What is the solution to this
sergeinik [125]

Answer:

D.) 8x^2+11x-9

Step-by-step explanation:

5x^2 -(-3x^2) =8x^2

7x -(-4x) =11x

-4 -5 =-9

Hope it helps

4 0
4 years ago
In which quadrant is (-1/2, -1.8)?
Anna71 [15]

Answer:

quadrant 3

Step-by-step explanation:

you go to the left 1/2 and down 1.8, putting you in quadrant 3

3 0
3 years ago
Read 2 more answers
A boat travels 30 miles up the river in the same amount of time it takes to travel 38 miles down the same river. If the current
Ksenya-84 [330]
X miles per hour  -  <span> speed of the boat in still water
(x - 2)  -  speed up the river
(x + 2)  -  speed down the river
</span>
\frac{30}{x - 2} = \frac{38}{x + 2}
30 * (x + 2) = 38 * (x - 2)
30x + 60 = 38x - 76
- 8x = - 136
x = 17 miles per hour  -  <span>the speed of the boat in still water.</span>
5 0
3 years ago
What is the length of the hypotenuse for a right triangle with legs of length 9 and 40? A) 41 B) 43 C) 45 D) 47
Katena32 [7]

Answer:

A) 41

Step-by-step explanation:

Let the hypotenuse be denoted by h

perpendicular as p and base as b

According to the Pythagoras theorem

h²=p²+b²

h =  \sqrt{ {p}^{2} +  {b}^{2}  }

h =   \sqrt{ {(40)}^{2}  +  {(9)}^{2} }

h =  \sqrt{1600 + 81}  =  \sqrt{1681}

h = 41

8 0
4 years ago
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
3 years ago
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