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o-na [289]
3 years ago
9

If the measure of ZDEF is 65°, what is the measure of DE?

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

I believe it is C because i heard of that one before

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Factorise 3x + 5x – 12​
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Answer:(x+3)(3x+4)

Step-by-step explanation:

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PLS HELP LOLZ <33
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Answer: tasha's investment will be worth $1,440

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If 9 people are rushing to sit down in just 5
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The answer would be 15,120



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2 years ago
Please help me out..(:
Nitella [24]

Let's call the left side of this tirangle y and downside z.

3² + 6² = y²

y² = 45

y² + z² = (3 + x)²

45 + z² = 9 + 6x + x²

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45 + x² + 6² = 9 + 6x + x²

45 + x² + 36 = 9 + 6x + x²

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4 0
3 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
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