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o-na [289]
3 years ago
9

If the measure of ZDEF is 65°, what is the measure of DE?

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

I believe it is C because i heard of that one before

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Repost 8th grade 50 POINTS+BRAINLIEST: How do you graph a quadratic equation in vertex form when the equation is a perfect squar
Naddika [18.5K]

Answer: Vertex : Maximum (2, 0)

Rules:

  • (x + d)² = x² + 2dx + d²    and   (x - d)² = x² - 2dx + d²
  • x² + 2dx = (x + d)² - d²   and  x² - 2dx = (x - d)² - d²

Solve:

x² - 4x + 4

x² - 2(2x) + 2²

(x - 2)²

Into vertex form: a(x - h)² + k

1(x - 2)² + 0

Identify:

vertex : (h, k) = (2, 0)

Find additional things, to graph the equation:

(i) x-intercept: (2, 0)

(ii) y-intercept: (0, 4)

Graph shown:

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1 year ago
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The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

y>1

3 0
3 years ago
Find the circumference of each circle with the given radius or diameter. Round to the nearest tenth. Use 3.14 for T.
GuDViN [60]

Answer:

C=44.6mm

Step-by-step explanation:

C=pi times d

C=3.14 times 14.2

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3 years ago
1) Use the rules of exponents to evaluate or simplify. Write without negative exponents.
AlladinOne [14]
1)\\ 3*4^0=3*1=3\\\\ 2)\\ a^{-b=(\frac{1}{a})^b}}\\
\frac{1}{4^{-2}}=\frac{1}{(\frac{1}{4})^2}=\frac{1}{\frac{1}{16}}=1*\frac{16}{1}=16
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Solve for x (hint - use the quadratic formula):
geniusboy [140]

Step-by-step explanation:

find the value of sec X/3

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