Answer:
No
Step-by-step explanation:
VX = 4 spaces
UW = 3 spaces
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Answer:
It's probably it
Step-by-step explanation:
A = (-4, -2)
B = (1, 6)
Imagine a new point (C) where they intersect (1, -2)
Now we can form a triangle, the distance between A and B will be the hypotenuse.
h² = 5² + 8²
h² = 25 + 64
h² = 89
h = 
h = ~9.43...
h = 9
So you need to find the $ for one hour of work
if 16=135
1 hour= $8.50
$8.50*24= $204
answer=$204
hope this helps :)
Answer:
The unit rate = 7/10 cranes per minute
Step-by-step explanation:
So, the number of minutes would it would take Kenny to fold 1505 cranes is
10/7 x 1505 = 2150 minutes
2150/60 = 35 5/6 hours
