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Alenkinab [10]
3 years ago
7

IT takes chris 9 hours longer to construct a fence than it take tony. If they work together, they caan construct the fence in 20

hours. How long would it take each man working alone?
Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

Tony = 36 Hours

Chris = 45 Hours

Step-by-step explanation:

let y+9 = Chris's time to build the fence alone

let y = Tony's time

let the completed job = 1

20/y+9 + 20/y = 1

Multiply the equation by y(y+9)

20y + 20(y+180) = y(y+9)

20y + 20y + 180 = y^2 + 9y

40 y + 180 = y^2 + 9y

0 = y^2 + 9y -40y - 180

y^2 - 31y - 180

(y + 5)(y - 36) = 0

y + 5 = 0

y = 0 - 5

y = -5 We reject this answer since we're only interested in the positive answer in terms of work done by two people.

y - 36 = 0

y = 0 + 36

y = 36  hours

So Chris takes y + 9 hours more than Tony

Chris's Time = y + 9  

Chris's Time = 36 + 9

Chris's Time = 45 hours

olga_2 [115]3 years ago
5 0

ANSWER

Tony: 36 hours

Chris: 45 hours

EXPLANATION

If it takes Tony x hours to construct the fence, then it will take Chris (x+9) hours.

Tony's rate is

\frac{1}{x}

Chris' rate is

\frac{1}{x + 9}

Their combined rate in terms of x is

\frac{1}{x}  +  \frac{1}{x + 9}

Their combined rate must equal

\frac{1}{20}

This implies that;

\frac{x + 9 + x}{x(x + 9)}  =  \frac{1}{20}

\frac{2x + 9 }{x(x + 9)}  =  \frac{1}{20}

Cross multiply,

x(x + 9) = 20(2x + 9)

Expand;

{x}^{2}  + 9x = 40x + 180

This implies that,

{x}^{2}  + 9x - 40x - 180 = 0

{x}^{2}   - 31x - 180 = 0

{x}^{2}  - 36x  + 5x - 180 = 0

(x - 36)(x + 5) = 0

x = 36 \: or \: x =  - 5

We discard the negative value.

Hence

x = 36

Therefore it will take Tony 36 hours and Chris 45 hours.

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Answer:

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Step-by-step explanation:

Un sistema de ecuaciones lineales es un conjunto de dos o más ecuaciones de primer grado, en el cual se relacionan dos o más incógnitas.

Resolver un sistema de ecuaciones consiste en encontrar el valor de cada incógnita para que se cumplan todas las ecuaciones del sistema.

En este caso, las variables a calcular son:

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Una empresa aceitera ha envasado 3000 litros de aceite en 1200 botellas de dos y de cinco litros. Entonces es posible plantear el siguiente sistema de ecuaciones:

\left \{ {{2*x+5*y=3000} \atop {x+y=1200}} \right.

Existen varios métodos para resolver un sistema de ecuaciones. Resolviendo por el método de sustitución, que consiste en despejar o aislar una de las incógnitas y sustituir su expresión en la otra ecuación, despejas x de la segunda ecuación:

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x= 1000

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