The cinematic equation is:
h (t) = (1/2) * a * t ^ 2 + vo * t + h0
Where,
a: acceleration
vo: initial speed
h0: initial height
Substituting values:
h (t) = (1/2) * (- 32) * t ^ 2 + (0) * t + 9
h (t) = - 16t ^ 2 + 9
For t = 0.2 we have:
h (0.2) = - 16 * (0.2) ^ 2 + 9
h (0.2) = 8.36 feet
To touch the ground we have:
-16t ^ 2 + 9 = 0
16t ^ 2 = 9
t = root (9/16)
t = 0.75 s
Answer:
The height of the cherry after 0.2 seconds is:
h (0.2) = 8.36 feet
the cherry hits the ground at:
t = 0.75 s
Answer:
b
Step-by-step explanation:
all squares have 4 sides which is a quadrilateral.
i uploaded a vid on this here
https://www.you tube.com/watch?v=dQw4w9WgXcQ
its actually c tho..
Answer:
PK=8.49m
Explanation:
We have sine formula

By sine formula we have

We have PS = 12, ∠P=105° and ∠S=30°, so ∠K=180°-(105°+30°)=45°
Substituting
Circumference of circular track, C = 0.5 miles = 0.5×5280 feet = 2640 feet.
We know, circumference in circle is given by :

( Here, r is radius i.e distance of centre from track )
Putting values in above equation :
2 × 3.14 × r = 2640
6.28 × r = 2640
r = 420.38 feet
Therefore, distance between centre and track is 420.38 feet .
Hence, this is the required solution.