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3 years ago

The diameter of the figure to the left is 9 cm.

Mathematics

1 answer:

Leviafan [203]3 years ago

8 0

Answer:

?????????

Step-by-step explanation:

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Which table represents a linear function?

Romashka-Z-Leto [24]

Answer:

1st one

Step-by-step explanation:

Since the x's for each one are going up by the same number, you are looking for a column of y's to either by going up by the same number or down by the same number.

The first table has a column of y's that look like this: 1/2 , 1 , 1 1/2, 2

This is actually going up for 1/2 each time.

This table shows a linear function.

8 0

3 years ago

In the figure, angle K measures 45 degrees. What is the measurement of angle C?

Delvig [45]

It is 45 because the triangle should be 180 degree and if K is 45 then J should be 45, too. We all know that the right triangle is 90 degree, so we add angle J and G, it is 135. Lastly, you subtract 180- 135=45.

5 0

3 years ago

Help i dont understand how to complete this

Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

Step-by-step explanation:

$Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8$

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9 --> 10.8 + 9 = 19.8

Danny: x --> 10.8

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2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3 (x = -1 is an extraneous solution so is not valid)

2d) No Solution (x = 1 is an extraneous solution so is not valid)

Here is the work for 2a. Follow this format for b, c, & d

$\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}$

$x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}$

8 0

3 years ago

Find P(x) in the following equation. 23 + 3.02 – 43 – 4 = P(2)(x + 2) + 8

Studentka2010 [4]

It’d be the last (4th) option. x^2+x-6

first you’d subtract 8 from both sides, and then divide by x+2

5 0

2 years ago

Choose the equation that represents the graph below: Graph of a line passing through points 0 comma 4 and 3 comma 0 y = −three f

belka [17]

(0,4),(3,0)
slope = (0 - 4) / (3 - 0) = -4/3

y = mx + b
slope(m) = -4/3
ur y int is when x = 0....so it is 4
and in y = mx + b form, the slope is in the m position and the y int is in the b position
so ur equation is : y = -4/3x + 4 <==

8 0

2 years ago

Read 2 more answers