<img src="https://tex.z-dn.net/?f=2%28a%2B11%29%3D-3%2816-a%29%5C%5C%5C%5C%20also%20this%5C%5C2%28x%2B10%29%3D2%283x-8%29" id="T

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3 years ago

exFormula1" title="2(a+11)=-3(16-a)\\\\ also this\\2(x+10)=2(3x-8)" alt="2(a+11)=-3(16-a)\\\\ also this\\2(x+10)=2(3x-8)" align="absmiddle" class="latex-formula">
can ya'll solve this for me please

Mathematics

1 answer:

adell [148]3 years ago

8 0

Answer:

sorry no

Step-by-step explanation:

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We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

<u>Step-by-step explanation:</u>

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

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