Answer:
The answer is B.
Step-by-step explanation:
Hope it helps!!
Ah hah ! You said in there "race AGAIN". Tell us something about how the first race turned out, and we may have some information we can use to answer with. Right now we got nuttn.
Answer:
The answer is below
Step-by-step explanation:
Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.
Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.
In quadrilateral ABCD:
∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)
Substituting:
47 + 39 + 112 + ∠D = 360
∠D + 198 = 360
∠D = 360 - 198
∠D = 162°
The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:
∠A = ∠E = 47°
∠B = ∠F = 39°
∠C = ∠G = 112°
∠D = ∠H = 162°
The answer to your question is 12
Since it is a parallelogram cente at point T,
then the measure of PT is equal to the measure of TR. And the measure of QT is
equal to the measure of TS.
PT = TR
a + 4 = 2a
4 = 2a -a
a = 4
PT = TR = 8 units
QT = TS
b = 2b -3
3 = 2b – b
b = 3
<span>QT = TS = 3 units</span>
