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astraxan [27]
3 years ago
8

30 271 24 21 18 15 12 9 6 3 23 5 6 7 8 9 10

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

Answer:

???

Step-by-step explanation:

antiseptic1488 [7]3 years ago
6 0

Answer:

was this just free points?

Step-by-step explanation:

I want to help you

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PLSSS HELP What is the formula for the following arithmetic sequence? -2, 3, 8, 13, ... an = -2n + 3 an = -2n + 7 an = 5n + 3 an
san4es73 [151]

Answer:

  an = 5n -7

Step-by-step explanation:

Try the offered formulas with n= 1 and see which gives you the first term of the sequence.

<u>an = -2n +3</u>

  -2(1) +3 = 1 . . . . not -2

<u>an = -2n +7</u>

  -2(1) +7 = 5 . . . . not -2

<u>an = 5n +3</u>

  5(1) +3 = 8 . . . . not -2

<u>an = 5n -7</u>

  5(1) -7 = -2 . . . . this is the formula you want

_____

If you recognize the common difference of the sequence to be 5, then you can automatically eliminate any formulas that don't contain 5n.

7 0
4 years ago
There are 10 girls and 8 boys in Mr Augello's class
poizon [28]
Whats the rest of the question
7 0
3 years ago
Read 2 more answers
Need help with this math question
Valentin [98]

Answer:

0.01097393689

Step-by-step explanation:

We can use the equation f(n) = 8*1/3^n-1 to find the nth term in this sequence. 8 being the first term, 1/3 being the common ratio

5 0
3 years ago
Suppose that pulse rates among healthy adults are normally distributed with a mean of 80 beats/second and a standard deviation o
olga_2 [115]

Answer:

0.3520

Step-by-step explanation:

We have been given that the pulse rates among healthy adults are normally distributed with a mean of 80 beats/second and a standard deviation of 8 beats/second. We are asked to find the proportion of healthy adults have pulse rates that are more than 83 beats/sec.

First of all, we will find z-score corresponding to sample score of 83 as:

z=\frac{x-\mu}{\sigma}, where,

z = Z-score,

x = Sample score,

\mu = Mean,

\sigma = Standard deviation.

Upon substituting our given values in z-score formula, we will get:

z=\frac{83-80}{8}=\frac{3}{8}=0.375\approx 0.38

Now, we need to find the probability that a z-score is greater than 0.38.

Using formula P(z>a)=1-P(z, we will get:

P(z>0.38)=1-P(z

Using normal distribution table, we will get:    

P(z>0.38)=1-0.64803

P(z>0.38)=0.35197

P(z>0.38)\approx 0.3520

Therefore, 0.3520 of healthy adults have pulse rates that are more than 83 beats/sec.

8 0
4 years ago
So I was walking down the street, but something stopped me in my tracks. It was 1 mil bobux! I went to tell my friend, RTX morsh
Vera_Pavlovna [14]

Answer:

aah maf 899999

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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