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Fynjy0 [20]
3 years ago
5

PLS PLS ANSWER SOMEONE​

Mathematics
1 answer:
LenKa [72]3 years ago
3 0

Answer:

the answer i think it is 5

im not 100% sure on what the question is, but i hope this helps

Step-by-step explanation:

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A. 55<br> B. 45<br> C. 90<br> D.35
Dima020 [189]

Answer:

I believe it is A

Step-by-step explanation:

I really hope it's right

I hope you have a wonderful day!

5 0
3 years ago
Read 2 more answers
F(1)=15<br> f(n)=f(n-1)*n<br> What does f(2) equal?
Arlecino [84]

Answer:

f(2) =30

Step-by-step explanation:

f(1)=15

f(n)=f(n-1)*n

Put in n=2

f(2)=f(2-1)*2

     = f(1) *2

      = 15*2

       =30

3 0
3 years ago
Read 2 more answers
A relish is prepared by the following recipe:
givi [52]

The weight of relish prepared after the evaporation of water is 2,226.02 pounds

<h3>Percentage</h3>

  • pickles = 1000 pounds
  • onions = 500 pounds
  • sugar = 900 pounds
  • salt brine = 75 pounds
  • spices = 5 pounds

Total = 1000 + 500 + 900 + 75 + 5

= 2,480 pounds

pickles are 92% water

= 92/100 × 1000

= 920 pounds

onions are 85% water

= 85/100 × 500

= 425 pounds

salt brine is 88% water

= 88/100 × 75 pounds

= 66 pounds

Total water in the mixture = 920 pounds + 425 pounds + 66 pounds

= 1,411 pounds

  • Percentage of water evaporated = 18%

Amount of water evaporated = 18/100 × 1,411 pounds

= 253.98 pounds

Weight of the relish prepared = 2,480 pounds - 253.98 pounds

= 2,226.02 pounds

Learn more about percentage:

brainly.com/question/843074

#SPJ1

5 0
3 years ago
Can someone plz help
GREYUIT [131]

Answer:

-9.56

Step-by-step explanation:

5 0
3 years ago
The probability of drawing a red candy at random from a bag of 25 candies is 2/5. After 5 candies are removed from tehe bag, wha
yaroslaw [1]

Given:

The probability of drawing a red candy at random from a bag of 25 candies is \dfrac{2}{5}.

To find:

The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.

Solution:

Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:

P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}

\dfrac{2}{5}=\dfrac{n}{25}

\dfrac{2}{5}\times 25=n

10=n

After removing the 5 candies from the bag, the number of remaining candies is 25-5=20 and the number of remaining red candies is 10-5=5.

Now, the probability of randomly drawing a red candy from the bag is:

P(Red)=\dfrac{5}{20}

P(Red)=\dfrac{1}{4}

Therefore, the required probability is \dfrac{1}{4}.

3 0
3 years ago
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