Answer this for brainliest answer

Two trucks, 36 feet apart, are towing a large field mower. If the lengths of the tow ropes are 27 feet and 19 feet, find the ang

FrozenT [24]

acute or obtuse yes yay

6 0

3 years ago

R/3+2=21 solve for r

olchik [2.2K]

Answer:

r=63

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

r/3-(21)=0 r

Simplify —

3

r

— - 21 = 0

3 2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

21 21 • 3

21 = —— = ——————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

7 0

3 years ago

What are the first four terms in the sequence Tn=4n+9?

marysya [2.9K]

Answer: If the initial term of an arithmetic sequence is a 1 and the common difference of successive members is d, then the nth term of the sequence is given by: a n = a 1 + (n - 1)d The sum of the first n terms S n of an arithmetic sequence is calculated by the following formula: S n = n (a 1 + a n)/2 = n [2a 1 + (n - 1)d]/2

6 0

2 years ago

Can you answer this math homework? Please!

Kay [80]

Step-by-step explanation:

$x + 3y = 7 \\ 2x + 4y = 8 \\ x = 7 - 3y \\ 2(7 - 3y) + 4y = 8 \\ 14 - 6y + 4y = 8 \\ 14 - 2y = 8 \\ - 2y = - 6 \\ y = 3 \\ x = 7 - 3(3) \\ x = 7 - 9 \\ x = - 2$

8 0

3 years ago

Read 2 more answers

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago