Answer:
![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
Step-by-step explanation:
Given inequality is ![\[−7\geq13−5x\]](https://tex.z-dn.net/?f=%5C%5B%E2%88%927%5Cgeq13%E2%88%925x%5C%5D)
Simplifying:
![\[5x\geq13+7\]](https://tex.z-dn.net/?f=%5C%5B5x%5Cgeq13%2B7%5C%5D)
![\[=>5x\geq20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E5x%5Cgeq20%5C%5D)
![\[=>x\geq \frac{20}{5}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%20%5Cfrac%7B20%7D%7B5%7D%5C%5D)
![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
Hence the solution for the given inequality is represented by ![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
This means that the original inequality will be true only for those values of x which are greater than or equal to 4.
Answer:
Do 16 times pi.
Step-by-step explanation:
The closest answer is D.
Answer:
This sum is the sum of an arithmetic sequence. There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.
A nice approach for this sequence is the following. Notice that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.
There are n of these pairs. So the desired sum is n x (first number + last number). But the first number is 1 and the last on is 2n. Thus the desired sum is n(1 + 2n).
Hope this helps!!
Mark Brainleast!!!!!!!!!!!
Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way
Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
=-180
find the sum =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.
so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
18 18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u> 18 10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"
=(18n-3)(10n-3)
therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
I think it should be B because the depth of the water should be decreasing slowing at the same rate.