Ask question

Ask question

All categories

2 years ago

5

Mr. Powell rents a storage space that is 7 feet high, 5 feet long, and 4 feet wide.

1 answer:

FrozenT [24]2 years ago

8 0

Answer:

To find how many 1 by 1 containers can fit in his storage space we must find the volume of the storage space in cubic feet. The formula for the volume of a rectangular prism aka the room is length x width x height. With this formula, all we need to do is plug in all the values given to the variables.

volume = length x width x height = 5 x 4 x 7 = 20 x 7 = 140

Final Answer: 140 one foot by one foot containers can fit in Mr. Powell's storage space

You might be interested in

Which is a true statement?

GarryVolchara [31]

d is true

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Suppose f(x)=x^2. what is the graph of g(x)=f(3x)?<br>

Katarina [22]

Answer:

D

Step-by-step explanation:

because since there is no negative sign in front of the 3x we automatially know there is no reflection so that rules out answers A and B. Then, since 3 is greater than 1 we can determine that it is a stretch which would rule out answer C so the answer is D

6 0

2 years ago

Someeee one?????????????????

Ad libitum [116K]

Answer:

Option B) $a_{n} = 2\cdot 4^{n-1}$

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

$a_{n} = a_{1}\cdot r^{n-1}$

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

$r=\frac{8}{2} = 4$

You can try other consecutive numbers too, you will get the same common ratio

$r=\frac{32}{8} = 4$

$r=\frac{128}{32} = 4$

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

$a_{n} = 2\cdot 4^{n-1}$

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

$a_{n} = 2\cdot 4^{n-1}$

Lets find out the 2nd term

Substitute n = 2

$a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8$

Lets find out the 3rd term

Substitute n = 3

$a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32$

Lets find out the 4th term

Substitute n = 4

$a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128$

Lets find out the 5th term

Substitute n = 5

$a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512$

Hence, we are getting correct results!

6 0

2 years ago

HELP GEOMETRY PROOFS

Reptile [31]

Step-by-step explanation:

See the attached for the proof

6 0

2 years ago

Solve linear equations -4(b+3)-12=2b-16+5b

daser333 [38]

Answer:

$Exact form:b=-\frac{8}{11}\\Decimal form: b=-0.72727272727272727272$

Step-by-step explanation:

$-4(b+3)-12=2b-16+5b$

$-4b-12-12=2b+5b$

$-4b-24=7b-16$

$-4b=7b+8$

3 0

2 years ago

Read 2 more answers