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astra-53 [7]
2 years ago
10

16+2.4c=22.5 what does c equal?

Mathematics
2 answers:
Zepler [3.9K]2 years ago
7 0
Subtract both sides by 16 because u want to get the variable by itself then divide that by 2.4
Savatey [412]2 years ago
6 0
Rmember you can do anything to an equaiton as long as you it to both sides also x-x=0 and x times 1/x=1 and x times 1=x 16+2.4c=22.5 subtract 16 from both sides 2.4c=6.5 multiply both sides by 1/2.4 1c=2.708333333333333
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PLEASE HELP ITS DUE REALLY SOON!!!
oksian1 [2.3K]

Answer:

-(5x-21)/6 so d

Step-by-step explanation:

to do inverse functions you want to replace the x in the function with y so x=(21-6y)/5, then solve for y and you will get the answer I got and its d

8 0
2 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
Really need help guys
DaniilM [7]
Sorry but can we get a better shot of the paper can barley see it
3 0
3 years ago
The distance to the nearest exit door is less than 150 feet.
Alja [10]

Answer:

d<150

Step-by-step explanation:

6 0
3 years ago
What is 5 1/4 x 4 1/5
dalvyx [7]

Answer:

The answer to your question is 22 1/20

5 0
2 years ago
Read 2 more answers
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