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Jobisdone [24]
3 years ago
12

Round to the nearest thousand 5.2182

Mathematics
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:

5.218

Step-by-step explanation:

5 or more, you add one. Four or less, you change it to zero.

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If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
A graph titled Passing Statistics has pass attempts on the x-axis, and yards on the y-axis. A line goes through points (24, 127)
bogdanovich [222]

Answer:

1/3x

Step-by-step explanation:

Subtract x by x and y by y to find the distance/difference

36            163

24,          127

= 12/36 = rise/run

Now reduce to find the slope, reduce until you can't anymore.

12/36

6/18

3/9

1/3 (that's your slope)

4 0
3 years ago
Solve the following equation -6p+7=3(2p-3)-4(-10+4p)<br> a.p=6<br> b.p=5<br> c.p=7<br> d.p=12
Ilia_Sergeevich [38]
Solve for p by simplifying both sides of the equation, then isolating the variable.
p=6
7 0
3 years ago
Aiko jumped rope for an amazing 20 minutes. She stoped at 8:05. When did she start jumping?
marissa [1.9K]
If she stopped at 8;05, and she started 20 minutes earlier, just imaging a clock at 8:05 and turn back time 20 minutes.

Five minutes would be 8:00, ten minutes is 7:55, fifteen minutes is 7:50, and twenty minutes is 7:45. This, she started at 7:45
4 0
3 years ago
Solve 5x + 8 &lt; 3(x + 2)
Vaselesa [24]
The answer i thinkkk would be,
x < -1
4 0
3 years ago
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