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Fed [463]
3 years ago
10

A model rocket is launched straight into the air from platform 3 feet above the ground with an intial velocity of 192 feet per s

econd
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

the function -16t^2 + 64t + 192 give the height S, in ft, of a model water rocket launched with a velocity of 64 ft/second from a hill that is 192 ft high. a) determine how long it will take the rocket to reach the ground, b) find the interval on which the height of the rocket is greater than 240 ft.

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Solve each equation. Record your work and check your solution. <br> a. 5(x-2)+(-9)= -7(1-x)
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The solution for equation is x = -6

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

5(x-2) + (-9) = -7(1-x)

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x

Solve for terms in left hand side of equation

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7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6

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