The answer is 69 not negative but positive <span />
It is D , 5 x 8 = 40, 5 x 3 = 15
Not sure I understand this but
5x+2=0
5x = -2
x = -2/5
Or
x = -.4
The system of equations has No solution.
<u>Step-by-step explanation</u>:
step 1 :
The given system of equations are
4x-8y=-16 -------- (1)
x-2y=-8 ----------- (2)
step 2 :
Taking 4 as common from equation (1)
4(x-2y) = 4(-4)
The equation (1) becomes x-2y = -4
- Now, equations (1) and (2) have same x and y terms and only constant is different.
- Therefore, the system of equations cannot be solved for x and y values. It has no solution.
step 3 :
From equation (2), find the value for x
x-2y = -8
x = 2y-8
step 4 :
Substitute x = 2y-8 in equation (1)
4x-8y = -16
4(2y-8) -8y = -16
8y - 32 -8y = -16
8y-8y = 32-16
It cannot be solve for x and y values.
∴ The system of equations has No solution.
Answer:
(a) (a · b) · c has Meaningless because it is the dot product of two scalars.
(b) (a · b)c has Meaningful because it is a scalar multiple of a scalar and a vector .
(c) |a|(b · c) has Meaningful because it is the product of two scalars .
(d) a · (b + c) has Meaningful because it is the dot product of two vectors .
(e) a · b + c has Meaningless because it is the sum of a scalar and a vector.
(f) |a| · (b + c) has Meaningless because it is the dot product of a scalar and a vector .
