The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
Answer:
25% .
Step-by-step explanation:
Because segments XY and XZ are of equal length, angle Y and angle Z must be congruent.
All inner angles must add to 180 degrees since it's a triangle.
70+70+x=180
140+x=180
x=40
Final answer: D
Answer:
thats helpful
Step-by-step explanation:
Well 2% of 6000 is 120. Then u take 120 times 12 (the amount of months in 1 year) than u take the answer (1440) and mulitply it by 15 (the amount of years) and get <span>21600.
Hope this helps! :3
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