Answer:
I might be able to help as long as there's no algebra involved
Answer:
58
Step-by-step explanation:
follow the pattern. The pattern is to take away 10, for each subsequent number.
Answer:
Eq: (x+a/2)²+(y+1)²=(a²-8)/4
Center: O(-a/2, -1)
Radius: r=0.5×sqrt(a²-8)
Mandatory: a>2×sqrt(2)
Step-by-step explanation:
The circle with center in O(xo,yo) and radius r has the equation:
(x-xo)²+(y-yo)²=r²
We have:
x²+y²+ax+2y+3=0
But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4
And
y²+2y+3=y²+2y+1+2=(y+1)²+2
Replacing, we get:
(x+a/2)²-a²/4+(y+1)²+2=0
(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4
By visual inspection we note that:
- center of circle: O(-a/2, -1)
- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)
Answer:
The amount of wire left is 4x + 1
Step-by-step explanation:
Initially, the wire is (7x - 3) meters long.
A length of (3x - 4) meters is cut.
How much wire is left?
Initial amount subtracted by the amount that is cut. So
(7x - 3) - (3x - 4) = 7x - 3 - 3x + 4
We combine the like terms
7x - 3x - 3 + 4 = 4x + 1
The amount of wire left is 4x + 1
