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3 years ago

Please help with 1234, due tonight would mean everything! Will give brainly!!

Mathematics

1 answer:

kolbaska11 [484]3 years ago

7 0

Answer: For 1, the answer is B since there is no rational number for sqrt17.

For 2, the answer is C since it has to be less than 11 whose square is 121 and larger than 10 whose squre is 100.

For 3 the answer is B. Just plug the x value into the equation. => y=1/2(-1)-2 => y= -1/2-2 => -2 1/2.

For 4 the answer is A because the graph first goes up then stys their staticly for a while then plumets down. It fits the description of the first one.

Step-by-step explanation:

Have a nice day, I hope next time you can solve it yourself! :D

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3 years ago

I need a legit answer with just a little explanation please it would mean alot to me

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2 years ago

felipe deposits $500 into a bank account that pays simple interest at a rate of 2% per year how much interest will be be paid in

Verdich [7]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$500\\ r=rate\to 2\%\to \frac{2}{100}\dotfill &0.02\\ t=years\dotfill &4 \end{cases} \\\\\\ I=(500)(0.02)(4)\implies I=40$

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2 years ago

the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

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4 years ago