Answer:
t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490
Step-by-step explanation:
Solve for t:
4.9 t^2 - 2.78 t - 1.15 = 0
4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:
(49 t^2)/10 - (139 t)/50 - 23/20 = 0
Multiply both sides by 10/49:
t^2 - (139 t)/245 - 23/98 = 0
Add 23/98 to both sides:
t^2 - (139 t)/245 = 23/98
Add 19321/240100 to both sides:
t^2 - (139 t)/245 + 19321/240100 = 75671/240100
Write the left hand side as a square:
(t - 139/490)^2 = 75671/240100
Take the square root of both sides:
t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490
Add 139/490 to both sides:
t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490
Add 139/490 to both sides:
Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490
Total = Principal * (1 + rate)^years
Total = 650 * (1.08)^14
<span>Total = 1,909.1</span>8
Answer:
8 and 10
Step-by-step explanation:
Our first step is to set x as the other side length, and y as the hypotenuse. We get that 6 + x + y = 24, and x + y = 18. The area gives us that 6x = 24(2) = 48. We then divide both sides by 6 and we get x = 8. We have x = 8 so we plug that into the equation x + y = 18 and we get that y = 10. So the other side lengths are 8 and 10.
Answer:
<u>A≈301.44</u>
Step-by-step explanation:
The area of a cylinder is A=2πrh+2πr^2
You first do the first problem of the equation (A=2πrh)
You fill in the radius and height ( A=2π(4)(8) )
You first multiply 4 x 8 = 32. ( A=2π(32) )
Then you multiply 2 x 32 = 64. ( A=π(64) )
Then you multiply π x 64 (using 3.14 for π) = 200.96 m^2
You then do the second part of the equation. (A=2πr^2)
You fill in the radius. (A=2π(4)^2)
Then multiply 4 x 4 = 16 (because it's to the power of 2 [4 times itself twice]) and then multiply it by 2.
16 x 2 = 32. ( A=π(32) )
Next you just multiply 32 x π (using 3.14 for π again) = 100.48 m^2.
Then you just add them together:
200.96 m^2 + 100.48 m^2 = 301.44 m^2
So <u>301.44 m^2</u> is your answer.
(I hopefully think it is.)
Given:
In triangle DEF, HG is parallel to DF.
To find:
The value of x.
Solution:
In triangles DEF and GEH,
(Common angle)
(Corresponding angle)
(By AA property of similarity)
We know that corresponding sides of similar triangle are proportional.
Isolating variable terms, we get
Therefore, the value of x is equal to 4.
