Answer:
14 and 6th I think correct me if I'm wrong this is for help not to cheat
The gallons of the first brand of antifreeze should be 60 gallons.
The gallons of the second brand of antifreeze should be 90 gallons.
<h3>What are the linear equations that represent the question?</h3>
0.2f + 0.45s = 52.50 (0.35 x 150) equation 1
f + s = 150 equation 2
Where:
- f = gallons of the first antifreeze
- s = gallons of the second antifreeze
how many gallons of each brand of antifreeze must be used?
Multiply equation 2 by 0.2
0.2f + 0.2s = 30 equation 3
Subtract equation 3 from equation 2
0.25s = 22.50
s = 22.50 / 0.25
s = 90
f = 150 - 90 = 60 gallons
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Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer: x = (-50)/3
<h3>
Answer is 1.5 square meters</h3>
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Work Shown:
The portion of the fabric that is laying across the ground is 2 meters. The portion of the fabric from the ground to the highest point (along the fabric's edge) is 1.5 meters, half of that is 0.75 meters and this is the length of the shadow. We can see this by forming a 30-60-90 triangle. The hypotenuse is 1.5 meters, the short leg is 0.75 meters. The short leg is always half of the hypotenuse of any 30-60-90 triangle, and the short leg is opposite the 30 degree angle.
So this shadow has length of 2 meters and 0.75 meters, making its area be 0.75*2 = 1.5 square meters when the sun is directly overhead at 12 noon
<h2>Answer</h2>
A. Angle E = 113°
B. x = 16°
<h2>Explain</h2>
<u>Number A</u>
92 + 70 + 85 + ? = 360
162 + 85 + ? = 360
247 + ? = 360
? = 360 - 247
? = 113°
<u>Number B</u>
108 + 84 + ( x + 30 ) + ( 2x + 18 ) = 360
(180 + 84 + 30 + 18) + (x + 2x) = 360
312 + 3x = 360
3x = 360 - 312
3x = 48
x = 48/3
x = 16°
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