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e-lub [12.9K]
3 years ago
14

Slope = -6; passes through (-4, 1) write a linear equation in slope intercept form with the given information

Mathematics
2 answers:
Eddi Din [679]3 years ago
5 0
I think it’s y=-6x -23
skad [1K]3 years ago
3 0

Answer: The Slope Intercept form is y=-6x-23

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Identify the best method for solving the given
PolarNik [594]
Elimination because u could multiply the second equation by -3 which would cancel the x and allow you to solve for y and then everntually x but yea elimination is the best method
4 0
3 years ago
The dot plot below represents a set of
mel-nik [20]
1, 3, 3, 4, 5, 6, each x is one of each number below
3 0
3 years ago
A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s
Setler [38]

Answer:

310\text{ feet and }210\text{ feet}

Step-by-step explanation:

GIVEN: A farmer has 520 \text{ feet} of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 310 \text{ feet}.

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be x and y

perimeter of rectangular pen =2(x+y)=520\text{ feet}

                                                x+y=260

                                               y=260-x

area of rectangular pen =\text{length}\times\text{width}

                                       =xy

putting value of y

=x(260-x)

=260x-x^2

to maximize \frac{d \text{(area)}}{dx}=0

260-2x=0

x=130\text{ feet}

y=390\text{ feet}

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen =310\text{ feet}

                              width of rectangular pen =210\text{ feet}

Maximum area of rectangular pen =310\times210=65100\text{ feet}^2

Hence maximum area of rectangular pen is 65100\text{ feet}^2 and dimensions are 310\text{ feet and }210\text{ feet}

5 0
3 years ago
Consider two people being randomly selected. (For simplicity, ignore leap years.)
inna [77]

Answer:

(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

=\frac{12}{365} X\frac{12}{365}  = \frac{144}{133225}

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on  same day of same month) = 1

P(2 people selected not having birthday on  same day of same month):

= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}

P(2 people selected have birthday on the same day of same month) = 1-\frac{364}{365} \\\\= \frac{1}{365}

7 0
3 years ago
X + y = -5 determine x-intercept and y-intercept
Fofino [41]

Very easy question.

To find x intercept: Multiply y by 0. You get x=-5.

To find y intercept: Multiply x by 0. You get y=-5.

4 0
3 years ago
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