The circle with center (h, k) and radius r has equation
.. (x -h)^2 +(y -k)^2 = r^2
You have
.. h = 2
.. k = 0
.. r = √5
The center is (h, k) = (2, 0).
Assuming m<PTQ is a right angle (measuring 90°) and angle TQP is already marked as 63° while knowing there are 180° in a triangle, you would take 180°- 63°- 90°= 27
Answer:
11x-8
Step-by-step explanation:
HARD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
1. A
2. D
not so sure about the last one
