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Feliz [49]
3 years ago
10

39. Rewrite each expression as an equivalent expression containing only one logarithm.

Mathematics
1 answer:
monitta3 years ago
3 0

Answer:

ln{\frac{(p+q)^3}{q^2p^7} }

Step-by-step explanation:

3 ln(p + q) − 2 ln(q) − 7 ln(p)

=ln(p+q)^3- ln(q)^2-ln(p)^7

= ln(p+q)^3-{ln(q)^2+ln(p)^7}

=ln(p+q)^3-ln(q)^2*(p)^7

=ln{ (p+q)^3÷(q)^2*(p)^7}

=ln{\frac{(p+q)^3}{q^2p^7} }

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Answer:

x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

Step-by-step explanation:

you have the following formula:

(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1

To solve this equation you use the following properties:

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Thne, by using this propwerty in the equation (1) you obtain for x

log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

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