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MAVERICK [17]
2 years ago
12

Anyone know this geometry question? 10 min left! Will give brainiest

Mathematics
1 answer:
Rasek [7]2 years ago
5 0
Angle 3 and angle 6 are corresponding angles, which means they are equal. In order for the lines to remain parallel, angle 3 and angle 6 would need to remain equal. If something is done to angle 6, then it would have to be done to angle 3 as well in order to keep the angles equal. So, if angle 6 is doubled, angle 3 would also have to be doubled. 

The answer is B. m< 3 would need to double.

Hope this helps =)
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An online file storage site offers a payment plan where users
lozanna [386]

Answer:   95.40

Step-by-step explanation:

7.95*12=95.40

6 0
2 years ago
Which two square numbers have a difference of 51
atroni [7]
49 and 100 are the answers as 100-49=51 and they are both square numbers as 100 square rooted is 10 and 49 square rooted is 7 is that a good enough answer please tell in comments
3 0
2 years ago
List the steps that should be used to solve the equation f(x) = g(x) by graphing when f(x) = (1/2)² - 3 and g(x) = 3x + 5?
jolli1 [7]

value of x is: x=\frac{-31}{12}

Step-by-step explanation:

We need to solve the equation f(x)=g(x)

where f(x)=(\frac{1}{2})^2-3

and g(x) = 3x + 5

Solving to find f(x)=g(x)

Putting values of f(x) and g(x)

f(x)=g(x)\\(\frac{1}{2})^2-3=3x + 5\\\frac{1}{4}-3=3x + 5\\Subtarct\,\,5\,\,on\,\,both\,\,sides:\\\frac{1}{4}-3-5=3x + 5-5\\\frac{1}{4}-8=3x\\Taking\,\,LCm\,\,on\,\,left\,\,side\\\frac{1-8*4}{4}=3x\\\frac{-31}{4}=3x\\Divide\,\,both\,\,sides\,\,by\,\,3\\x=\frac{-31}{4*3}\\x=\frac{-31}{12}

So, value of x is: x=\frac{-31}{12}

The graph will be a straight line x= -2.58 or x = -31/12

Keywords: Composition of Functions

Learn more about Composition of Functions at:

  • brainly.com/question/10772025
  • brainly.com/question/4939434
  • brainly.com/question/2723982
  • brainly.com/question/1774827

#learnwithBrainly

7 0
3 years ago
REWARDING 70 POINTS TO THOSE WHO GET IT RIGHT (MATH)
lilavasa [31]

Answer:

18y+8x=y

Step-by-step explanation:

pretty sure this is correct

3 0
2 years ago
Read 2 more answers
If three tangents to a circle form an equilateral triangle, prove that the tangent points form an equilateral triangle inscribed
weqwewe [10]
I added a figure so you can guide yourself throughout the proof I'm about to write, so I recommend that you download the picture beforehand and have this window and the picture's window open. Alright, let's get started!
Assuming that FED is an equilateral triangle according to the wording of the problem, we have that the angles \widehat{AFB}=\widehat{BEC}=\widehat{CDA}=60.
We also know that the circle in green is Inscribed in FED.

The following applies to every inscribed circle inside a triangle:
The center of the inscribed circle of a triangle is the intercept of all three angle bisectors of the triangle.

The above theorem implies that the line (FO) is an angle bisector because it goes through the vertex F and the center of the inscribed circle.

The previous statement implies that the angle \widehat{OFB}=30.

Now let's work on the OFB triangle.
Knowing that \widehat{OBF}=90 (because (EF) is tangent to the circle at B and OB is a radius of the circle. If you're lost here, remember that a tangent to a circle is always perpendicular to the radius of the circle.) we can then derive that \widehat{FOB}=180-90-30=60 (because the sum of the measures of all angles in a triangle is always equal to 180 degrees).

In the same way, we can prove also that:
\widehat{BOE}=\widehat{EOC}=\widehat{COD}=\widehat{DOA}=\widehat{AOF}=60 degrees.
Knowing the above we notice that \widehat{BOC}=\widehat{COA}=\widehat{AOB}=120degrees.

We're at the last part of our proof here:
Now notice that \widehat{BOA} subtends the same arc on the circle  that \widehat{BCA}.
According to the inscribed angle theorem, an angle \theta inscribed in a circle is half of the central angle 2\theta that subtends the same arc on the circle. 
Therefore \widehat{BCA}=\frac{\widehat{BOA}}{2}=60degrees

We can prove in a similar fashion that:  \widehat{CAB}=\widehat{ABC}=60degrees 
Therefore all the angles of the ABC triangle have a measure of 60 degrees, we conclude then that  ABC is equilateral.


5 0
2 years ago
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