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zhannawk [14.2K]
3 years ago
11

A tennis ball bounces based on this equation y = x2 - x+2. A dog jumps based on this equation y=2x.

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer: when the equations are equal, that is when  x = 1 or x = 2

Step-by-step explanation:

The dog will receive the ball , when both equations intercept , that is , when both equations are equal. This implies :

x^{2} - x + 2 = 2x

x^{2} - x - 2x + 2 = 0

x(x-1) - 2 (x - 1 ) = 0

(x - 1 ) ( x - 2 ) =0

Therefore , x = 1 or x = 2

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If r=0.5 and a6=0.03125 what is the value of a1?
andre [41]

I guess this is a geometric series:

a6 = a1 * r^5 so

a1 =  0.03125 / 0.5^5

=  1    answer

5 0
2 years ago
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A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

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IgorC [24]

Answer:

18 + 16 n

Step-by-step explanation:

does that equation equal anything??

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The answer would be 13/15
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Y=e^x how do I solve this
kolezko [41]
If you're trying to solve for x, keep in mind the ln (natural log) of e is 1. So take the natural log of both sides, which will give you ln Y = ln e^x. The ln and e essentially cancel out, so you're left with x = ln Y. 
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