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inessss [21]
3 years ago
7

What property is illustrated by this problem 45*0=0

Mathematics
1 answer:
Bingel [31]3 years ago
7 0

T​he zero property of multiplication

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Honey and Money are twin brothers. Mother wants to equally divide a rectangular shaped cake of 5cm wide and 6cm long. Find the l
tatuchka [14]

Answer:

Length of rectangular cake = 5 cm

Breadth of rectangular cake = 6 cm

Area of rectangle = 5 cm × 6 cm =30 cm²

If cake is equally distributed between Honey and Money, then areas of two parts should be equal.

So, Amount of cake that Honey and money got \frac{30}{2}=15

Share of each (Honey and Money)=15 cm²

So, if the third cake if it was cut diagonally ,the cake must have some height.

Let the height of cake be H.

So, Height of third cake =\sqrt{L^2+B^2+H^2}\\\\=\sqrt{5^2+6^2+H^2}\\\\=\sqrt{61+H^2}

If , H=0 that is height is negligible having 0 thickness,

Then the Length of third cake, which is divided into two parts=√61=7.81 cm

5 0
3 years ago
Evaluate each expression for a = -4, b = 3, and c = 2.<br> 4a²b-23
aleksklad [387]

Answer: -215

Please give brainliest

4 0
2 years ago
Solve the equation -9x+1=-x+17​
Step2247 [10]

Answer:

x=-2

Step-by-step explanation:

-9x+1=-x+17

Add 9x on both sides:

     1=8x+17

Subtract 17 on both sides:

   -16=8x

Divide both sides by 8:

     -2=x

Check x=-2!

-9x+1=-x+17     with x=-2

-9(-2)+1=-(-2)+17

18+1=2+17

19=19

19=19 is a true equation so x=-2 is correct.

5 0
2 years ago
Read 2 more answers
Rewrite sqr-100 +26 in complex number notation
Morgarella [4.7K]

Answer:

26 + 10i is your answer.

8 0
2 years ago
Solve 2x2 + 20x = −38. (1 point)
RoseWind [281]

Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

x^{2} +10x=-19 ------> x^{2} +10x+19=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


x=\frac{-10(+/-)\sqrt{24}}{2}


x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


8 0
2 years ago
Read 2 more answers
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