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mihalych1998 [28]
3 years ago
7

LM is 3x, MN is 2x+2. M is the midpoint of LN. What is LM?

Mathematics
1 answer:
Blababa [14]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

3x=(1/2)(2x+2)

3x=x+1

3x-x=x-x+1

2x=1

x=1/2

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2/5+x=1 What equals x?
kolbaska11 [484]

Answer:

Step-by-step explanation:

2/5 + x = 1

Multiply each term by 5

2 + 5x = 5

5x = 5 - 2

5x = 3

x = 3/5

8 0
4 years ago
Read 2 more answers
The radius of the cone is 5 in and y = 13 in. What is the volume of the cone in terms of π?
olga nikolaevna [1]

Answer:

The volume of the cone is;

100 π inches^3

Step-by-step explanation:

To calculate the volume, we need the height

We can get the height from the slant height and the radius

Mathematically, we use Pythagoras’ theorem for this as the slant height, the radius and the height forms a right-angled triangle

The right-angled triangle has the slant height as its hypotenuse

By the theorem, the square of the hypotenuse equals the sum of the squares of the two other sides

Let the height be h

Thus;

12^2 = 5^2 + h^2

169= 25 + h^2

h^2 = 169-25

h^2 = 144

h = √1144 inches = 12 inches

The volume of the cone is;

1/3 * π * r^2 * h

= 1/3 * π * 5^2 * 12

= 100 π inches^3

4 0
3 years ago
The ratio of Harry's money to Lincoln's money is 6:5. If Harry and Lincoln have a total of $220, how much money in dollars does
RideAnS [48]
Hehas 337 dollrs because 220:65% is one so that is it
4 0
3 years ago
What divided by what equals 253
Jet001 [13]

so 253 doubles is 506, 506 divided by two = 253
therefore the answer will be '' 506 divided by 2 = 253''
6 0
3 years ago
Find the measures of the acute angles of the right triangle shown
yanalaym [24]

9514 1404 393

Answer:

  • 2x° = 64°
  • (x-6)° = 26°

Step-by-step explanation:

The acute angles in a right triangle are complementary:

  2x° +(x -6)° = 90°

  3x = 96 . . . . . . . . . divide by °, add 6

  x = 32 . . . . . . . . . divide by 3

  (x-6)° = (32 -6)° = 26°

  2x° = 2(32)° = 64°

The acute angles have measures 26° and 64°.

7 0
3 years ago
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