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Solnce55 [7]
2 years ago
5

(PLZ FAST- 30 PTS)Which expressions are equivalent?

Mathematics
2 answers:
Digiron [165]2 years ago
5 0

Answer:

A. 3x-7y and -7y+3x

Step-by-step explanation:

Let x=1, y=2

3(1)-7(2)

3-14

-11

-7(2)+3(1)

-14+3

-11

Vera_Pavlovna [14]2 years ago
4 0
The answer is

3x-7y and -7y+3x
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What is the upper quartile of the data set shown?
IrinaK [193]

Answer:

12,13,15,16 i believe

Step-by-step explanation:

6 0
2 years ago
Also need help with this
Crank
=7(∛2x) - 6(∛2x) - 6(<span>∛x)
= </span>∛2x - 6<span>∛x

answer
C. </span>∛2x - 6∛x
third choice
6 0
3 years ago
Given: AB with point C between A and B. AB = 10x + 20, AC = 2x + 13, and CB = 10x - 9.
Feliz [49]

Answer:46

Step-by-step explanation:

7 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
Maria must choose a number between 61 and 107 that is a multiple of 5, 6, and 10. Write all the numbers that she could choose. I
RSB [31]
Multiples of 5 : 65,70,75,80,85,90,95,100,105
multiples of 6 : 66,72,78,84,90,96,102
multiples of 10 : 70,80,90,100

she could choose : 90...and thats it
4 0
3 years ago
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