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3 years ago

(PLZ FAST- 30 PTS)Which expressions are equivalent?

Mathematics

2 answers:

Digiron [165]3 years ago

5 0

Answer:

A. 3x-7y and -7y+3x

Step-by-step explanation:

Let x=1, y=2

3(1)-7(2)

3-14

-11

-7(2)+3(1)

-14+3

-11

Vera_Pavlovna [14]3 years ago

4 0

The answer is

3x-7y and -7y+3x

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3 years ago

Jean spines two spinners. The results of both spins are shown. Tell whether the events are dependent or independent. Explain you

leva [86]

Th answer is D.) The spin on the first spinner does not affect the spin on the second, so the events are dependent.

The reason D is the answer is because, no matter what one spinners results are it does not effect the other spinner and its results, so that takes out answer choices a and c. Now we're left with whether the events are independent or dependent. Well, the results are not independent because they are caused by the effect of an outward force (The person spinning the spinner). They also show the end result of the change, and we use them to record the results, so they are dependent.

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3 years ago

Erica makes 14 an hour working 40 hrs a week what is her gross monthly income?

8_murik_8 [283]

40hrs/5days a week= 8hrs a day

£14x8=£112 a day

112x5= £560 a week

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3 years ago

A canister is dropped from a helicopter 500m above the ground. Its parachute does not open, but the canister has been designed t

solmaris [256]

Answer:

The impact speed 98.995 m/s is less than 100 m/s and the canister will not burst.

Step-by-step explanation:

A function F is called an antiderivative of f on an interval I if $F'(x) = f(x)$ for all x in I.

Recall that if the object has position function $s=f(t)$ , then the velocity function is $v(t)=s'(t)$ . This means that the position function is an antiderivative of the velocity function. Likewise, the acceleration function is $a(t)=v'(t)$ , so the velocity function is an antiderivative of the acceleration.

An object near the surface of the earth is subject to a gravitational force that produces a downward acceleration denoted by $g$ . For motion close to the ground we may assume that $g$ is constant, its value being about $9.8 \:{\frac{m}{s^2}}$ .

We know that the acceleration due to gravity is given by

$a(t)=-9.8$

and the antiderivative is velocity

$v(t)=\int a(t)\,dt\\v(t)=\int -9.8\,dt\\v(t)=-9.8t +C$

We know that the canister was dropped, so the initial velocity at t = 0 is zero, this fact let us know the value of C.

$v(0)=9.8(0)+C\\C=0$

The antiderivative of velocity is the position

$s(t)=\int v(t) \, dt\\s(t)=\int -9.8t \, dt\\s(t)=-4.9t^2+C$

To find the value of the constant C, we know that the height was 500 m at t = 0, this means $s(0)=500$

$500=-4.9(0)^2+C\\C=500$

$s(t)=-4.9t^2+500$

Using the fact that at the time of impact the height s(t) is zero we can compute the total time of the fall:

$s(t)=-4.9t^2+500=0\\\\-4.9t^2=-500\\\\t^2=\frac{5000}{49}\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\t=\sqrt{\frac{5000}{49}},\:t=-\sqrt{\frac{5000}{49}}$