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pochemuha
3 years ago
11

Ms Greene class has two chameleons. Lumpy total length is 12 inches and Larry is 6 inches. Each of their fails is twice as long

as its body. How long is lumpy tail
Mathematics
1 answer:
White raven [17]3 years ago
8 0
I believe it would be 6inches… I think
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An athlete ran 200 meters in 19.19 seconds. Suppose that he ran the first half of that race (around a curve) in 10.75 seconds. H
SOVA2 [1]

The time needed to run the second half of the race is 8.44 s

Step-by-step explanation:

The total distance covered by the athlete during the race is

d = 200 m

And the total time taken to cover this distance is

T = 19.19 s

We also know that the time the athlete needs to cover the first half of the race is

t_1 = 10.75 s

Also, we know that

T=t_1 + t_2

where t_2 is the time the athlete takes to cover the second half of the race.

Re-arranging this equation and susbtituting the values, we find the value of t2:

t_2 = T-t_1 = 19.19-10.75=8.44 s

Learn more about uniform motion:

brainly.com/question/8893949

#LearnwithBrainly

5 0
3 years ago
HELP ME PLEASE ASAP,,,,,,,
JulsSmile [24]

Answer:

a) i) The drawing of Zeno's route is attached

ii) The bearing of Zeno's return journey is 241° from point C to point A

b) Yes, Zeno returns to Port A before 5.15pm

Step-by-step explanation:

a) i) Please find attached the drawing of Zeno's route

ii) From the attached diagram of Zeno's route created with Microsoft Whiteboard, we find the bearing of his return journey as 241° from point C to point A

b) The distance from point C to point A = 10·√5 km

The speed with which Zeno sails as he returns = 10 km/h

The time it takes Zeno to return t = Distance/Speed

∴ The time it takes Zeno to return t = 10·√5 km/(10 km/h) = √5 h ≈ 2.2361 hours ≈ 2 hours 14 minutes and 9.845 seconds

The time Zeno arrives at point A from point A ≈ 3.00 pm + 2 hours 14 minutes and 9.845 seconds = 5:14.1641 p.m. ≈ 5:14 pm.

Therefore, Zeno returns to Port A before 5.15pm.

5 0
3 years ago
Trigonometric area formula: Area = The area of triangle EFG is 34.4 square units. What is the perimeter of triangle EFG to the n
Airida [17]
29 units, just got  it right on e2020.
8 0
4 years ago
Read 2 more answers
Simplify each expression, and classify the the result as rational or irrational.
tatiyna

1. Not rational

2. Rational

3. Not rational

4. Rational

5. Rational

6. Not rational

<em>(had help from a calculator, nonetheless hope it helps :D)</em>

8 0
4 years ago
How many 4-letter passords can be made using the letters A thought Z if...
mezya [45]

Answer:

a.)The total 4-letters passwords when repetition of letters is allowed are 456976

b.)The total 4-letters passwords when repetition of letters is not allowed are 358800

Step-by-step explanation:

Some situations of <em>probability</em> involve multiple events. When one of the events affects others, they are called dependent events. For example, when objects are chosen from a list or group and are not returned, the first choice reduces the options for future choices.

There are two ways to sort or combine results from dependent events. <em>Permutations</em> are groupings in which the order of objects matters. <em>Combinations</em> are groupings in which content matters but order does not.

How many 4-letter passwords can be made using the letters A throught Z if...

a)Repetition of letters is allowed?

There are only 26 possible values for each letter of the password (The English Alphabet consists of 26 letters). The total 4-letters passwords when repetition of letters is allowed are 26^{4} =456976

b) Repetition of letters is not allowed?

If repetition of  letters is not allowed, we can only choose 4 letters out of 26. Using the permutation equation nP_{k} =\frac{n!}{(n-k)!}

The total 4-letters passwords when repetition of letters is not allowed are 26P_{4} =\frac{26!}{(26-4)!}=26.25.24.23=358800

.

7 0
3 years ago
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