The equation of the circle that passes through the point (0 , 4) and has a center at the origin is x^2 + y^2 = 16.
Using the distance formula, get the radius of the circle by solving for the distance between the center and the point (0 , 4).
radius = distance = √(x2 - x1)^2 + (y2 - y1)^2
radius = √(0 - 0)^2 + (4 - 0)^2
radius= √0 + 16
radius = 4
The standard form of the equation of the circle is given by (x - h)^2 + (y - k)^2 = r^2, where (h , k) is the location of the center and r is the radius of the circle.
Given the radius and center of the circle, substitute these values to the standard form of the equation of the circle.
(x - h)^2 + (y - k)^2 = r^2
where (h , k) = (0 , 0)
r = 4
(x - 0)^2 + (y - 0)^2 = 4^2
x^2 + y^2 = 16
Learn more about equation of a circle here: brainly.com/question/14150470
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Answer: 6/11
Step-by-step explanation:
28 - 7 = 21
16 + 11 - 21 = 6
11 - 6 = 5
16-6 = 10
10 + 5 15
P (a) = 16/28
p (b) = 11/28
A I B = 6/28/11/28 = 6/11
I think the answer is C though i'm not entirely sure please tell me I'm right or I'm wrong
8 + 6 + 9 + 12 + 4x / 5 = x Original Problem.
25 + 4x / 5 = x Addition.
25 + 4x = 5x Multiply each side by 5.
25 = x Subtract 4x from each side.
x = 25 Switch equation around.
Answer: x = 25
174 - 150 is 24, so the angle IJF is 24 degrees :)