Answer:
The value at x =3 is undefined for the given expression
Step-by-step explanation:
Given expression is 
To find for what value of x is undefined in the given expression :



If we put x=3 in the above expression we get



Therefore 
The value at x =3 is undefined for the given expression
$150 (budget) - $30 (spend on herself) = $120 (left)
120 / 15 = $8
(150 - 30) divided by 15 = $8
Only $8 maximum can be spent on each family member
Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps